1x^2-4x+12=0

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Solution for 1x^2-4x+12=0 equation:


Simplifying
1x2 + -4x + 12 = 0

Reorder the terms:
12 + -4x + 1x2 = 0

Solving
12 + -4x + 1x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-12' to each side of the equation.
12 + -4x + -12 + x2 = 0 + -12

Reorder the terms:
12 + -12 + -4x + x2 = 0 + -12

Combine like terms: 12 + -12 = 0
0 + -4x + x2 = 0 + -12
-4x + x2 = 0 + -12

Combine like terms: 0 + -12 = -12
-4x + x2 = -12

The x term is -4x.  Take half its coefficient (-2).
Square it (4) and add it to both sides.

Add '4' to each side of the equation.
-4x + 4 + x2 = -12 + 4

Reorder the terms:
4 + -4x + x2 = -12 + 4

Combine like terms: -12 + 4 = -8
4 + -4x + x2 = -8

Factor a perfect square on the left side:
(x + -2)(x + -2) = -8

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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